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Temporada 2024
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2024x4
The mystery of 0.8660254037844386467637231707529361834714026269051903140279034897...
Episode overview
What's up with this strange number coincidence
What's up with this strange number coincidence
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This episode has no summary.
2024x6
The beautiful maths which makes 5G faster than 4G, faster than 3G, faster than...
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2024x12
The mathematically impossible ball that shouldn’t exist.
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We believe that the "there must exist a single-angle polyhedron for any angle θ with an algebraic sine" conjecture is true but don't have a nice proof. There seem to be all the required
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We believe that the "there must exist a single-angle polyhedron for any angle θ with an algebraic sine" conjecture is true but don't have a nice proof. There seem to be all the required parts for the proof in papers by Sydler and Jessen, but it's not fully assembled.
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2024x23
We shot a YouTube video about film formats on 35mm film
Episode overview
We shot a YouTube video about film formats on 35mm film
We shot a YouTube video about film formats on 35mm film
2024x24
My UK election prediction was weirdly accurate: am I a mathematical genius?
Episode overview
My UK election prediction was weirdly accurate: am I a mathematical genius?
My UK election prediction was weirdly accurate: am I a mathematical genius?
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2024x27
New largest prime number found! See all 41,024,320 digits.
Episode overview
2^136,279,841 - 1 has 41,024,320 digits and is prime! Read all about the new largest prime number ever found
2^136,279,841 - 1 has 41,024,320 digits and is prime! Read all about the new largest prime number ever found
2024x28
What do we know about Asteroid 314159 aka ‘Mattparker’?
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2024x30
Can the "Red Mirage" and "Blue Shift" be explained with math? ELECTION 2024
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With a trusted 3rd party, running Secret Santa is easy: The 3rd party labels each person 1,…,n, and then randomly chooses a derangement from among all possible derangements of n numbers.
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With a trusted 3rd party, running Secret Santa is easy: The 3rd party labels each person 1,…,n, and then randomly chooses a derangement from among all possible derangements of n numbers. Person i will then give a gift to the number in position i of the derangement. The trusted 3rd party is responsible for keeping the derangement secure, and for telling each person whom to give a gift to.
The question is: Is there an algorithm that would allow Secret Santa to be played without a trusted 3rd party?
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