Mystery Road: Origin

  • in première gegaan: Jul 2022
  • Afleveringen: 6
  • Volgers: 18
  • Lopend
  • ABC (AU)
  • Zondag op 20
  • Crime Drama

Seizoenen:

Log in om afleveringen als gekeken te markeren. Inloggen of aanmelden.

Seizoen 1
1x1
Episode 1
Episode overview
Uitzenddatum
Jul 03, 2022
Police constable Jay Swan starts a new job in an outback mining town where he spent his youth. While investigating a series of robberies and pursuing the truth behind a personal tragedy, he meets the love of his life.
1x2
Episode 2
Episode overview
Uitzenddatum
Jul 10, 2022
After a bizarre robbery, Jay leads a visit to a local gang that quickly escalates; Anousha seeks clues about Josh Allen's death; after the town's celebrations at the annual debutante ball, Jay's night takes a tragic turn.
1x3
Episode 3
Episode overview
Uitzenddatum
Jul 17, 2022
Jay struggles with findings about Jack's death. He looks for clues pointing to foul play and he fights with Geraldine about how best to commemorate his father. Anousha searches for people involved with Josh's case.
1x4
Episode 4
Episode overview
Uitzenddatum
Jul 24, 2022
Jay discovers Jack was deeply in debt and when Sputty also seems to be involved he becomes suspicious. Jay and Mary grow closer, Anousha acts for Ziggy and the Kelly Gang unexpectedly strikes again.
1x5
Episode 5
Episode overview
Uitzenddatum
Jul 31, 2022
After another heist by the Kelly Gang, Jay pieces together their identities and uncovers their hideout. Anousha finds an unexpected detail of the police investigation into Josh's death and suddenly finds herself in danger.
1x6 Seizoensfinale
Episode 6
Episode overview
Uitzenddatum
Aug 07, 2022
The Kelly Gang's plans violently come to a head in a shootout at the Roadhouse. Mary gets too close to Josh's killers and Jay finds out who was really behind his father's death. (Final)

Als er afleveringen of banners missen (en ze staan op TheTVDB), dan kun je een automatische update van de serie aanvragen:

Update van serie aanvragen

karakters

Als je dit leuk vindt, dan misschien ook: