Jeopardy!
Stefanie Tomko, Alex Hooper, Sue Romberg (2009x79)
Uitzenddatum: Apr 21, 2009
Sue Romberg, a homemaker & volunteer from Grapevine, Texas; Alex Hooper, a lawyer originally from Cedar Key, Florida; Stefanie Tomko, a software project manager from Bellevue, Washington (whose 1-day cash winnings total $20,800).
- in première gegaan: Sep 1984
- Afleveringen: 9218
- Volgers: 90
- Lopend
- Syndication
- Maandag op 19