Jeopardy!
Stefanie Tomko, Alex Hooper, Sue Romberg (2009x79)
Ημερομηνία προβολής: Απρ 21, 2009
Sue Romberg, a homemaker & volunteer from Grapevine, Texas; Alex Hooper, a lawyer originally from Cedar Key, Florida; Stefanie Tomko, a software project manager from Bellevue, Washington (whose 1-day cash winnings total $20,800).
- Πρώτη προβολή: Σεπ 1984
- Επεισόδια: 9203
- Ακόλουθοι: 90
- Τρέχων
- Syndication
- Δευτέρα στο 19